Integrand size = 15, antiderivative size = 208 \[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=-\frac {8 b^3 \sqrt {b \sqrt [3]{x}+a x}}{77 a^2}+\frac {24 b^2 x^{2/3} \sqrt {b \sqrt [3]{x}+a x}}{385 a}+\frac {12}{55} b x^{4/3} \sqrt {b \sqrt [3]{x}+a x}+\frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {4 b^{15/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{77 a^{9/4} \sqrt {b \sqrt [3]{x}+a x}} \]
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Time = 0.17 (sec) , antiderivative size = 208, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.467, Rules used = {2029, 2043, 2046, 2049, 2036, 335, 226} \[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=\frac {4 b^{15/4} \sqrt [6]{x} \left (\sqrt {a} \sqrt [3]{x}+\sqrt {b}\right ) \sqrt {\frac {a x^{2/3}+b}{\left (\sqrt {a} \sqrt [3]{x}+\sqrt {b}\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{77 a^{9/4} \sqrt {a x+b \sqrt [3]{x}}}-\frac {8 b^3 \sqrt {a x+b \sqrt [3]{x}}}{77 a^2}+\frac {24 b^2 x^{2/3} \sqrt {a x+b \sqrt [3]{x}}}{385 a}+\frac {12}{55} b x^{4/3} \sqrt {a x+b \sqrt [3]{x}}+\frac {2}{5} x \left (a x+b \sqrt [3]{x}\right )^{3/2} \]
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Rule 226
Rule 335
Rule 2029
Rule 2036
Rule 2043
Rule 2046
Rule 2049
Rubi steps \begin{align*} \text {integral}& = \frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {1}{5} (2 b) \int \sqrt [3]{x} \sqrt {b \sqrt [3]{x}+a x} \, dx \\ & = \frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {1}{5} (6 b) \text {Subst}\left (\int x^3 \sqrt {b x+a x^3} \, dx,x,\sqrt [3]{x}\right ) \\ & = \frac {12}{55} b x^{4/3} \sqrt {b \sqrt [3]{x}+a x}+\frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {1}{55} \left (12 b^2\right ) \text {Subst}\left (\int \frac {x^4}{\sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right ) \\ & = \frac {24 b^2 x^{2/3} \sqrt {b \sqrt [3]{x}+a x}}{385 a}+\frac {12}{55} b x^{4/3} \sqrt {b \sqrt [3]{x}+a x}+\frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}-\frac {\left (12 b^3\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{77 a} \\ & = -\frac {8 b^3 \sqrt {b \sqrt [3]{x}+a x}}{77 a^2}+\frac {24 b^2 x^{2/3} \sqrt {b \sqrt [3]{x}+a x}}{385 a}+\frac {12}{55} b x^{4/3} \sqrt {b \sqrt [3]{x}+a x}+\frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {\left (4 b^4\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b x+a x^3}} \, dx,x,\sqrt [3]{x}\right )}{77 a^2} \\ & = -\frac {8 b^3 \sqrt {b \sqrt [3]{x}+a x}}{77 a^2}+\frac {24 b^2 x^{2/3} \sqrt {b \sqrt [3]{x}+a x}}{385 a}+\frac {12}{55} b x^{4/3} \sqrt {b \sqrt [3]{x}+a x}+\frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {\left (4 b^4 \sqrt {b+a x^{2/3}} \sqrt [6]{x}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {x} \sqrt {b+a x^2}} \, dx,x,\sqrt [3]{x}\right )}{77 a^2 \sqrt {b \sqrt [3]{x}+a x}} \\ & = -\frac {8 b^3 \sqrt {b \sqrt [3]{x}+a x}}{77 a^2}+\frac {24 b^2 x^{2/3} \sqrt {b \sqrt [3]{x}+a x}}{385 a}+\frac {12}{55} b x^{4/3} \sqrt {b \sqrt [3]{x}+a x}+\frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {\left (8 b^4 \sqrt {b+a x^{2/3}} \sqrt [6]{x}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b+a x^4}} \, dx,x,\sqrt [6]{x}\right )}{77 a^2 \sqrt {b \sqrt [3]{x}+a x}} \\ & = -\frac {8 b^3 \sqrt {b \sqrt [3]{x}+a x}}{77 a^2}+\frac {24 b^2 x^{2/3} \sqrt {b \sqrt [3]{x}+a x}}{385 a}+\frac {12}{55} b x^{4/3} \sqrt {b \sqrt [3]{x}+a x}+\frac {2}{5} x \left (b \sqrt [3]{x}+a x\right )^{3/2}+\frac {4 b^{15/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{77 a^{9/4} \sqrt {b \sqrt [3]{x}+a x}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.10 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.51 \[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=\frac {2 \sqrt {b \sqrt [3]{x}+a x} \left (-\left (\left (5 b-11 a x^{2/3}\right ) \left (b+a x^{2/3}\right )^2 \sqrt {1+\frac {a x^{2/3}}{b}}\right )+5 b^3 \operatorname {Hypergeometric2F1}\left (-\frac {3}{2},\frac {1}{4},\frac {5}{4},-\frac {a x^{2/3}}{b}\right )\right )}{55 a^2 \sqrt {1+\frac {a x^{2/3}}{b}}} \]
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Time = 2.04 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.78
method | result | size |
default | \(\frac {\frac {262 a^{3} b^{2} x^{\frac {5}{3}}}{385}+\frac {56 a^{4} b \,x^{\frac {7}{3}}}{55}+\frac {4 b^{4} \sqrt {-a b}\, \sqrt {\frac {a \,x^{\frac {1}{3}}+\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (a \,x^{\frac {1}{3}}-\sqrt {-a b}\right )}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {a \,x^{\frac {1}{3}}+\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{77}-\frac {16 a^{2} b^{3} x}{385}+\frac {2 a^{5} x^{3}}{5}-\frac {8 a \,b^{4} x^{\frac {1}{3}}}{77}}{a^{3} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}}\) | \(163\) |
derivativedivides | \(\frac {2 a \,x^{2} \sqrt {b \,x^{\frac {1}{3}}+a x}}{5}+\frac {34 b \,x^{\frac {4}{3}} \sqrt {b \,x^{\frac {1}{3}}+a x}}{55}+\frac {24 b^{2} x^{\frac {2}{3}} \sqrt {b \,x^{\frac {1}{3}}+a x}}{385 a}-\frac {8 b^{3} \sqrt {b \,x^{\frac {1}{3}}+a x}}{77 a^{2}}+\frac {4 b^{4} \sqrt {-a b}\, \sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x^{\frac {1}{3}}-\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{77 a^{3} \sqrt {b \,x^{\frac {1}{3}}+a x}}\) | \(196\) |
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\[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=\int { {\left (a x + b x^{\frac {1}{3}}\right )}^{\frac {3}{2}} \,d x } \]
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\[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=\int \left (a x + b \sqrt [3]{x}\right )^{\frac {3}{2}}\, dx \]
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\[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=\int { {\left (a x + b x^{\frac {1}{3}}\right )}^{\frac {3}{2}} \,d x } \]
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\[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=\int { {\left (a x + b x^{\frac {1}{3}}\right )}^{\frac {3}{2}} \,d x } \]
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Time = 9.09 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.19 \[ \int \left (b \sqrt [3]{x}+a x\right )^{3/2} \, dx=\frac {2\,x\,{\left (a\,x+b\,x^{1/3}\right )}^{3/2}\,{{}}_2{\mathrm {F}}_1\left (-\frac {3}{2},\frac {9}{4};\ \frac {13}{4};\ -\frac {a\,x^{2/3}}{b}\right )}{3\,{\left (\frac {a\,x^{2/3}}{b}+1\right )}^{3/2}} \]
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